8t+4.9t^2=3.27

Solution for 8t+4.9t^2=3.27 equation:

8t+4.9t^2=3.27

We move all terms to the left:

8t+4.9t^2-(3.27)=0

We add all the numbers together, and all the variables

4.9t^2+8t-3.27=0

a = 4.9; b = 8; c = -3.27;
Δ = b2-4ac
Δ = 82-4·4.9·(-3.27)
Δ = 128.092
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(8)-\sqrt{128.092}}{2*4.9}=\frac{-8-\sqrt{128.092}}{9.8}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(8)+\sqrt{128.092}}{2*4.9}=\frac{-8+\sqrt{128.092}}{9.8}
$